5v^2+11v+5=0

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Solution for 5v^2+11v+5=0 equation: 



5v^2+11v+5=0

a = 5; b = 11; c = +5;
Δ = b2-4ac
Δ = 112-4·5·5
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{21}}{2*5}=\frac{-11-\sqrt{21}}{10}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{21}}{2*5}=\frac{-11+\sqrt{21}}{10}
$

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